The moment of force F=i^+j^+k^ acting at points (- 2,3, 4) about point (1, 2, 3) is

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4j-k

4(j-k)

4(j-3k)

4(j+k)

answer is B.

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Detailed Solution

r =r1 -r2=(- 2i^+3j^ + 4k^) -(i^+2j^ + 3k^)=-3i^+j^+k^Moment of the force = r x F=ijk-311111 = i^(1 -1) + j^ (1 + 3) + k^ (-3 -1)=8j-4k- 4(j-k)

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