The moment of inertia of a body about a given axis is 1.2 kg-m2. Initially, given axis the body is at rest. In order to produce a rotational kinetic energy of 1500 J and angular acceleration of 25 rads-2 a torque that must be applied about that axis for a duration of

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4 s

2 s

8 s

10 s

answer is B.

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Detailed Solution

As, I=1.2 kg⋅m2, Er=1500 J, α=25 rads−2, ω1=0, t=?Now, Er=12Iω2⇒ω=2ErI =2×15001.2=50 rads−1From ω2=ω1+αt 50=0+25t ⇒ t=2 s

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