The moment of inertia of a circular loop of of mass M and radius radius R, about an axis at a distance of R/2 parallel to horizontal diameter of loop is [AIIMS 2012]
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a
MR2
b
12MR2
c
2MR2
d
34MR2
answer is D.
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Detailed Solution
According to theorem of parallel axes,I=ICM+MR22⇒ I=12MR2+MR24Moment of inertia, I=34MR2
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The moment of inertia of a circular loop of of mass M and radius radius R, about an axis at a distance of R/2 parallel to horizontal diameter of loop is [AIIMS 2012]