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Q.

The moment of inertia of a circular loop of of mass M and radius  radius R, about an axis  at a distance of R/2  parallel to horizontal diameter of loop is [AIIMS 2012]

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a

MR2

b

12MR2

c

2MR2

d

34MR2

answer is D.

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Detailed Solution

According to theorem of parallel axes,I=ICM+MR22⇒ I=12MR2+MR24Moment of inertia,  I=34MR2
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The moment of inertia of a circular loop of of mass M and radius  radius R, about an axis  at a distance of R/2  parallel to horizontal diameter of loop is [AIIMS 2012]