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The moment of inertia of HCl molecule about an axes passing through its centre of mass perpendicular to the bond is (Given inter nuclear distance angstrom, mass of proton
detailed solution
Correct option is C
I=(m1m2m+m2)r2=1×351+351.32amu A0 = 3536×1.7×10-27×1.3×10-102 =2.79×10-47kgm2Talk to our academic expert!
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The radius of gyration of a rod of length L and mass M about an axis perpendicular to its length and passing through a point at a distance L/3 from one of its ends is
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