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The moment of inertia of HCl molecule about an axes passing through its centre of mass perpendicular to the bond is (Given inter nuclear distance d=1.3 angstrom, mass of proton 1.7×1027Kg.At.Wt of Cl is 35).

 

a
2.79×10−42Kgm2
b
2.79×10−44Kgm2
c
2.79×10−47Kgm2
d
2.79×10−49Kgm2

detailed solution

Correct option is C

I=(m1m2m+m2)r2=1×351+351.32amu A0 = 3536×1.7×10-27×1.3×10-102 =2.79×10-47kgm2

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