Q.
Moment of inertia of the isosceles right angled triangle ABC about the side BC is I. Then its moment of inertia about side AC is
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a
I2
b
2I3
c
I2
d
I3
answer is A.
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Detailed Solution
I=IBC=16. mAB2=16ma2 AB=BC=a∴ IAC = 16. m.ABsin45o2=16.m.a212=I2
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