Questions
Moment of inertia of the isosceles right angled triangle ABC about the side BC is I. Then its moment of inertia about side AC is
a
I2
b
2I3
c
I2
d
I3
detailed solution
Correct option is A
I=IBC=16. mAB2=16ma2 AB=BC=a∴ IAC = 16. m.ABsin45o2=16.m.a212=I2Talk to our academic expert!
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Two discs have mass ratio 1 : 2 and diameter ratio 2 : 1, then find the ratio of their moments of inertia.
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