Q.

Moment of inertia of the isosceles right angled triangle ABC about the side BC is I. Then its moment of inertia about side AC is

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a

I2

b

2I3

c

I2

d

I3

answer is A.

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Detailed Solution

I=IBC=16. mAB2=16ma2  AB=BC=a∴   IAC =  16.  m.ABsin45o2=16.m.a212=I2
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