Moment of inertia of ring about its diameter is I. The moment of inertia of the same ring about that axisperpendicular to its plane and passing through centre is [KCET 2014]

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answer is B.

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Detailed Solution

For a ring, Iz=MR2From perpendicular axes theorem, Ix+Iy=Iz …(i)Given, Ix=Iy=IFrom Eq. (i), we get2I=Iz