First slide

Moment of intertia

Question

Moment of inertia of ring about its diameter is I. The moment of inertia of the same ring about that axis
perpendicular to its plane and passing through centre is [KCET 2014]

Moderate

A

$\frac{I}{2}$
B

2I
C

$\frac{I}{4}$
D

4I

Solution

For a ring, $I_{z} = M R^{2}$
From perpendicular axes theorem, $I_{x} + I_{y} = I_{z}$ …(i)
Given, $I_{x} = I_{y} = I$
From Eq. (i), we get
$2 I = I_{z}$

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