Questions
Moment of inertia of a ring about a tangent perpendicular to the plane of the ring is . Then moment of inertia of the same ring about a tangent lying in the plane of the ring is
detailed solution
Correct option is D
By parallel axis theorem, I=mR2+mR2=2mR2Now moment of inertia about a diameter =12mR2Moment of inertia about tangent ABIAB=12mR2+mR2=32mR2=32 x I2=3I4Talk to our academic expert!
Similar Questions
The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its mid-point and perpendicular to its length is I0 , Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
