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Q.

The moment of inertia of a ring of mass m and radius r about an axis, passing through the centre and perpendicular to the plane of the ring, is:

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a

(1/2)mr2

b

mr2

c

(1/4)mr2

d

(3/4)mr2

answer is B.

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Detailed Solution

for a ring about an axis perpendicular to its plane and passing through its center is mr2 because all the masses are at a distance r from the axis.
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The moment of inertia of a ring of mass m and radius r about an axis, passing through the centre and perpendicular to the plane of the ring, is: