The moment of inertia of semicircular plate of radius R and mass M about axis AA' in its plane passing through its centre is
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a
MR22
b
MR24cos2(θ)
c
MR24sin2(θ)
d
MR24
answer is D.
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Detailed Solution
Moment of inertia of disk w.r.t. principle axis (1) =MR22Moment of inertia of disk w.r.t. diametrical axis (2)From perpendicular axes theoremIz=Ix+Iy…(i)here Ix=Iy, because both are diametrical axis,So here Iz=MR22and Ix=Iy=I( Let )So from eq. (i)⇒MR22=I+I⇒I=MR24For half disk also, it is applicable, SoI=MR24(It does not depend on θ given in diagram, because given axis is also similar to diametrical axis)