Moment of inertia of a solid disc about a diameter is I. Then moment of inertia of the disc about an axis which passes through a point on its circumference and perpendicular to the plane of the disc is

(1)I=14 mR2IC= Moment of inertia about an axis passing through the centre of the disc and perpendicular to the plane of the disc. = 2I=12 mR2∴  By parallel axis Theorem.I'=IC+ mR2=12 mR2+mR2=32mR2= 32× 4I=6I