Questions
The moment of inertia of sphere is 20 kg- about the diameter. The moment of inertia about any tangent will be-
detailed solution
Correct option is A
According to the theorem of parallel axes, the haveI=IG+Ma2=25MR2+MR2(∵a=R)=75MR2 Given that 25MR2=20 or MR 2=20×52=50, ∴I=75×50=70kg−m2Talk to our academic expert!
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The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its mid-point and perpendicular to its length is I0 , Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is
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