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Moment of inertia of a thin rod of mass M and length L about an axis passing through its centre is ML212. lts moment of inertia about a parallel axis at a distance of L4 from this axis is given by

a
ML248
b
ML248
c
ML212
d
7ML248

detailed solution

Correct option is D

Apply parallel axis theoremI = Icm+Mh2 = ML212+ML42= 7 ML248

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