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The moment of inertia of a thin square plate ABCD of uniform thickness about an axis passing through the centre O and perpendicular to the plate is:

(i) I1 + I2 
(ii) I3 + I4
(iii) I1+ I3 
(iv) I1 + I2+ I3 + I4
where I1 ,I2, I3 and l4 are respectively the moments of inertia
about axes 1,2,3 and 4 which are in the plane of the plate.

a
(i, ii)
b
(ii, iii)
c
(i, iv)
d
(i, ii, iii)

detailed solution

Correct option is D

It is a square plate so by symmetry, I3 = I4 and I1 = I2By perpendicular axis theorem, I0 = I1 + I2 + I3 + I4

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