First slide

Moment of intertia

Question

The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its mid-point and perpendicular to its length is I₀ , Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is

Easy

A

$I_{0} + M L^{2} / 4$
B

$I_{0} + 2 M L^{2}$
C

$I_{0} + M L^{2}$
D

$I_{0} + M L^{2} / 2$

Solution

According to parallel axes theorem, we have
$I_{x^{'} y^{'}} = I_{x y} + M d^{2}$
$= I_{0} + M {(\frac{L}{2})}^{2}$
$\Rightarrow I_{x^{'} y^{'}} = I_{0} + \frac{M L^{2}}{4}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App