Moment of inertia of a uniform circular disc about a diameter is I. Its moment of inertia about an axis perpendicular to its plane and passing through a point on its rim will be
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a
5I
b
3I
c
6I
d
4I
answer is C.
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Detailed Solution
I = 14MR2 ⇒ MR2 = 4Iwe have to find: I' = 32MR2 = 324I = 6I