Moment of inertia of uniform horizontal solid cylinder of mass M about an axis passing through its edge and perpendicular to the axis of the cylinder when its length is 6 times its radius R is
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a
39MR24
b
39MR4
c
49MR4
d
49MR24
answer is D.
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Detailed Solution
By parallel axis theoremI=MR24+ℓ23=MR24+(6R)23I=494MR2