Q.

The moment of inertia of a uniform thin rod of mass m and length l about two axis PQ and RS passing through centre of rod C and in the plane of the rod are IPQ and IRS respectively. Then IPQ+ IRS is equal to

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a

ml23

b

ml22

c

ml24

d

ml212

answer is D.

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Detailed Solution

The MI of of rod about axis PQ figure (a) and MI of rod about axis P'Q' figure (b) are same by symmetry.∴  IPQ+ IRS = IPQ+IRS = ml212by perpendicular axis theorem.
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The moment of inertia of a uniform thin rod of mass m and length l about two axis PQ and RS passing through centre of rod C and in the plane of the rod are IPQ and IRS respectively. Then IPQ+ IRS is equal to