The moment of inertia of a uniform thin rod of mass m and length l about two axis PQ and RS passing through centre of rod C and in the plane of the rod are IPQ and IRS respectively. Then IPQ+ IRS is equal to
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a
ml23
b
ml22
c
ml24
d
ml212
answer is D.
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Detailed Solution
The MI of of rod about axis PQ figure (a) and MI of rod about axis P'Q' figure (b) are same by symmetry.∴ IPQ+ IRS = IPQ+IRS = ml212by perpendicular axis theorem.