The moment of inertia of a wheel is 1000 kg-m2. At a given instant, its angular velocity is 10 rad/s. After the wheel rotates through an angle of 100 radians the wheel’s angular velocity is 100 rad/s. The torque applied on wheel is
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a
4.95×105N.m
b
4.95×104N.m
c
4.95×103N.m
d
49.5×105N.m
answer is B.
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Detailed Solution
We know that ω2−ω02=2αθ ∴α=ω2−ω022θ=(100)2−(10)22×100=49.5rad/s2 τ= I α=1000×49.5=4.95×104N−m