Questions
At a moment in a progressive wave, the phase of a particle executing S.H.M. is . Then the phase of the particle 15 cm ahead and at the time will be, if the wavelength is 60 cm
detailed solution
Correct option is D
Let the phase of second particle be φ. Hence phase difference between two particles is Δφ=2πλΔx⇒φ−π3=2π60×15⇒φ−π3=π2⇒φ=5π6Talk to our academic expert!
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The relation between phase difference () and path difference () is
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