First slide

Travelling wave

Question

At a moment in a progressive wave, the phase of a particle executing S.H.M. is $\frac{π}{3}$ . Then the phase of the particle 15 cm ahead and at the time $\frac{T}{2}$ will be, if the wavelength is 60 cm

Easy

A

$\frac{π}{2}$
B

$\frac{2 π}{3}$
C

Zero
D

$\frac{5 π}{6}$

Solution

Let the phase of second particle be $φ$ . Hence phase difference between two particles is $Δφ = \frac{2 π}{λ} Δx$
$\Rightarrow (φ - \frac{π}{3}) = \frac{2 π}{60} \times 15 \Rightarrow φ - \frac{π}{3} = \frac{π}{2} \Rightarrow φ = \frac{5 π}{6}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App