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The momentum of a body in two perpendicular direction at any time ‘t’ are given by $P_{x} = 2 t^{2} + 6$ and $P_{y} = \frac{3 t^{2}}{2} + 3$ . The force acting on the body at t = 2 sec is

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Correct option is C

F= dpdtFX=dpxdt=4t=4×2=8 N and FY=dpydt=3t =3×2=6 N⇒ F=F2X+FY2=82+62=10N

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The momentum of a body in two perpendicular direction at any time ‘t’ are given by Px=2t2+6 and Py=3t22+3 . The force acting on the body at t = 2 sec is

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Ready to Test Your Skills?

free study material

The momentum of a body in two perpendicular direction at any time ‘t’ are given by $P_{x} = 2 t^{2} + 6$ and $P_{y} = \frac{3 t^{2}}{2} + 3$ . The force acting on the body at t = 2 sec is