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The momentum of a body in two perpendicular direction at any time 't' are given by $P_{x} = 2 t^{2} + 6$ and $P_{y} = \frac{3 t^{2}}{2} + 3$ . The force acting on the body at t = 1 sec is

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Correct option is A

Fx=dPxdt=d2t2+6dt=4t ⇒Fy=dPydt=d3t22+3dt=32t2+0=3t F=Fx2+Fy2==4t2+3t2=5t=5×1=5 units

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The momentum of a body in two perpendicular direction at any time 't' are given by Px=2t2+6 and Py=3t22+3 . The force acting on the body at t = 1 sec is

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Ready to Test Your Skills?

free study material

The momentum of a body in two perpendicular direction at any time 't' are given by $P_{x} = 2 t^{2} + 6$ and $P_{y} = \frac{3 t^{2}}{2} + 3$ . The force acting on the body at t = 1 sec is