First slide

Second law

Question

The momentum of a body in two perpendicular direction at any time 't' are given by P_x= 2t² + 6 and $\large {P_y} = \frac{{3{t^2}}}{2} + 3$ . The force acting on the body at t = 2 sec is

Moderate

A

5 units
B

2 units
C

10 units
D

15 units

Solution

$\large {F_y} = \frac{{d{p_y}}}{{dt}} = 3t;{F_x} = \frac{{d{p_x}}}{{dt}} = 4t = 8$
$\large \therefore F = \sqrt {F_x^2 + F_y^2} = \sqrt {{6^2} + {8^2}} = 10N$

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