Questions
The momentum of inertia of a rod about an axis through its centre and perpendicular to it is (where M is the mass and L is the length of the rod). The rod is bent in the middle so that the two halfs make an angle of 60o. The moment of inertia of the bent rod about the same axis would be :
detailed solution
Correct option is B
IB=13(M/2)(L/2)2+13(M/2)(L/2)2=ML212Talk to our academic expert!
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