The momentum of inertia of a rod about an axis through its centre and perpendicular to it is $\frac{1}{12}{\mathrm{ML}}^2$ (where M is the mass and L is the length of the rod). The rod is bent in the middle so that the two halfs make an angle of 60^o. The moment of inertia of the bent rod about the same axis would be :

• A

  $\frac{1}{48}{\mathrm{ML}}^2$

• B

  $\frac{1}{12}{\mathrm{ML}}^2$

• C

  $\frac{1}{24}{\mathrm{ML}}^2$

• D

  $\frac{{\mathrm{ML}}^3}{8\sqrt{3}}$