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The momentum $p$ of a particle change with time t according to the relation $\frac{dp}{dt} = (10 + 2 t) .$ If the momentum is zero at t = 0, then the momentum at $t = 10 s is$

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Correct option is A

Given dpdt=10+2tdp=10+2tdt ⇒∫opdp=∫01010+2tdt ⇒p=(10t+t2)010 ⇒p=1010+102-10(0)+(0)2 ⇒p=200 kgms-1

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The momentum p of a particle change with time t according to the relation dpdt=10+2t. If the momentum is zero at t = 0, then the momentum at t=10 s is

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Ready to Test Your Skills?

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The momentum $p$ of a particle change with time t according to the relation $\frac{dp}{dt} = (10 + 2 t) .$ If the momentum is zero at t = 0, then the momentum at $t = 10 s is$