First slide

Vectors

Question

The momentum of a particle is p = i 2 cos t + j 2 sin t. what is the angle between the force F acting on the particle and the momentum p ?

Easy

A

45°
B

90°
C

135°
D

180°

Solution

$\begin{array}{l} F = \frac{dp}{dt} = - i 2 \sin t + j 2 \cos t \\ \cos θ = \frac{F \cdot p}{Fp} = 0 . Hence θ = 90^{\circ} \end{array}$

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