Quantum Theory of Light

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Question

The momentum of photon of energy 1 MeV will approximately be

Moderate

Solution

$P = \frac{E}{C} = \frac{{1 \times {{10}^6} \times 1.6 \times {{10}^{ - 19}}}}{{3 \times {{10}^8}}}\,;\,\,$
$\therefore P = 5 \times {10^{ - 22}}\,kg-m/s$

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