A monkey climbs up and another monkey climbs down a rope hanging from a tree with same uniform acceleration separately. If the respective masses of monkeys are in the ratio $$2$$ : $$3$$, the common acceleration must be

Question

A  monkey climbs up and another monkey climbs down a rope hanging from a tree  with same uniform acceleration separately.   If the respective masses of monkeys are in the ratio $$2$$ : $$3$$, the common  acceleration must be

Infinity Learn · Accepted Answer

Let  T is the tension of the rope.  When  monkey climbs up with acceleration a, then T−$$m1g=m1a$$      ……….(i)   When another monkey goes, down with  same acceleration a, then $$m2g$$−$$T=m2a$$                       …… (ii)Hence$$,  $$(m2$$−$$m1)g$$−$$T=(m1+m2)a$$     $$(or)  (1$$−$$m1m2)g=(m1m2+1)a$$     $$(or)(1$$−$$23)g=(23+1)a$$     $$(or)  $$a=g5$$

A monkey climbs up and another monkey climbs down a rope hanging from a tree with same uniform acceleration separately. If the respective masses of monkeys are in the ratio 2 : 3, the common acceleration must be

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