A monkey of mass 25 kg is holding a vertical rope. The rope does not break, if a body of mass 30 kg issuspended from it, but the rope breaks, if the mass of the body suspended with the rope exceeds 30 kg. What will be the maximum acceleration with which the monkey can climb up along the rope? (Take, g = 10 ms-2) [JCECE 2012]

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

2 ms-2

25ms-2

3 ms-2

4 ms-2

answer is A.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

The maximum weight which can be suspended with the rope without breaking it = 30 kg-wt.or Fmax=30×10=300 N∴ 300=mg+ma⇒ ma=300-mg=300-25×10=50 N⇒ a=50m=5025=2 ms-2

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE