A mono atomic gas (γ =5/3) is suddenly compressed to 1/8th of it’s volume adiabatically then the pressure of the gas will change to (times the initial pressure):
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a
24/5
b
8
c
40/3
d
32
answer is D.
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Detailed Solution
in an adiabatic processP1V1γ=P2V2γ ---(1) here P1 ,P2 are initial and final pressure of the gas V1,V2 are initial and final volume of the gasγ is specific heat ratio=53if V1=1,then V2=18 ⇒ P2=P1V1V2γ from equation (1) ⇒P2=P111853 ⇒P2=P1853 ⇒P2=P125 ⇒P2=P132