A mono atomic ideal gas at temperature T is expanded adiabatically to eight times its initial volume. Then final temperature of the gas is
T4
T32
T8
T2
δ=f+2f=3+23=53
Now T2T1=(V1V2)δ−1⇒T2T=(V18V1)53−1=1(23)23=14
⇒T2=T4