Questions
A mono atomic ideal gas at temperature T is expanded adiabatically to eight times its initial volume. Then final temperature of the gas is
detailed solution
Correct option is A
δ=f+2f=3+23=53Now T2T1=(V1V2)δ−1⇒T2T=(V18V1)53−1=1(23)23=14⇒T2=T4Talk to our academic expert!
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During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
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