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Q.

A mono atomic ideal gas at temperature T is expanded adiabatically to eight times its initial volume. Then final temperature of the gas is

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a

T4

b

T32

c

T8

d

T2

answer is A.

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Detailed Solution

δ=f+2f=3+23=53Now T2T1=(V1V2)δ−1⇒T2T=(V18V1)53−1=1(23)23=14⇒T2=T4
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