Questions
A monoatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16 V. The final pressure of the gas is (Take = 5/3)
Remember concepts with our Masterclasses.
80k UsersReady to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is C
First, isothermal expansion PV=P′(2V)(For isothermal process, PV = constant)P′=P2Then, adiabatic expansionP′(2V)γ=Pf(16V)γ (For adiabatic process, PVγ= constant )P2(2V)5/3=Pf(16V)5/3Pf=P22V16V5/3=P2185/3=P21235/3=P2125=P64Similar Questions
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
