Q.

A monoatomic ideal gas, initially at temperature  T1  is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to expand adiabatically to a temperature  T2 by releasing the piston suddenly. If   L1,L2  are the lengths of the gas column before and after expansion respectively, then  T1/T2 is given by :

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

(L1/L2)2/3

b

L2/L1

c

L1/L2

d

(L2/L1)2/3

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

In adiabatic process, relation between  temperature T and Volume V is TVγ-1=constant, here γ is specific heat ratio⇒T1V1γ-1=T2V2γ-1⇒T1T2=V2V1γ−1volume V= Area of base x height given V1=AL1V2=AL2, for monoatomic gas γ=53⇒T1T2=AL2AL15/3−1⇒T1T2=L2L12/3
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon