To mop-clean a floor, a cleaning machine a circular mop of radius R vertically down with a total force F and rotates it with a constant angular speed about its axis If the force F is distributed uniformly over a mop and if coefficient of friction between the mop and the floor is μ . The torque, applied by the machine on the mop is
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a
μFR3
b
μFR6
c
μFR2
d
23μFR
answer is D.
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Detailed Solution
Force on the small area element FπR2(dA) Frictional torque on then elements area dT=μ(FπR2)dAr=rμ(FπR2)2πrdrOn integrating T=μFπR22πR33=2μFR3