A mosquito is moving with a velocity  v→=0.5t2 i∧+3t j∧+9 k∧m/s and accelerating in uniform conditions. What will be the direction of mosquito after 2s?

v→=0.5t2i^+3tj^+9k^At t = 2s,v→=2i^ + 6j^ + 9k^v→=22+62+92=11Hence, v^=v→v→=211i^ + 611j^ + 911k^With y axis, let say angle made is β,cosβ=611⇒β=cos-1611