For most practical temperature we may take it that all bodies radiate heat in proportion to the fourth power of temperature T. If a body (coated black) at 400 K surrounded by atmosphere at 300 Khas cooling rate r0, the same body at 900 K, surrounded by the same atmosphere, will have cooling rate closer to
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a
81×80r0/175
b
81r0/16
c
16r0
d
4 r0
answer is A.
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Detailed Solution
According to Stefan's law, r0=σ4004−3004 and r=σ9004−3004rr0=(900)4−(300)4(400)4−(300)4=163∴ r=81 ×80175r0