The motion of a particle along a straight line is described by equation x = 8 + 12t - t3 where, x is in meter and t in second. The retardation of the particle when its velocity becomes zero, is
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a
24 ms-2
b
zero
c
6 ms-2
d
12 ms-2
answer is D.
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Detailed Solution
Given, x = 8 + 12t - t3We know that, v = dxdt and a = dvdtSo, v = 12 - 3t2and t = 2s, v = 0and a = -12 ms-2So, retardation of the particle = 12 ms-2.