The motion of a particle along a straight line is described by equation : x = 8 +12t -t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is
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a
12 ms-2
b
24 ms-2
c
zero
d
6 ms-2
answer is A.
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Detailed Solution
v = dxdt = 12-3t2 ---(i)If velocity is zero, 12-3t2 = 0 which gives t = 2 secFor acceleration again differential equation (i)a = d2xdt2 = -6t----(ii)At time t = 2 sec, a = -6×2 = -12 m/s2Hence retardation = 12 m/s2