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Questions  

The motion of a particle along a straight line is described by the function x=(2t-3)2, where x is in meters and t is in seconds. Find the position, velocity and acceleration at t=2s.

a
1m,4m/s,8m/s2
b
1m,5m/s,7m/s2
c
1m,3m/s,2m/s2
d
5m,4m/s,8m/s2

detailed solution

Correct option is A

Position, x=(2t-3)2  Velocity,   v=dxdt=4(2t-3)m/s  and acceleration, a=dvdt=8 m/s2at t=2s,  x=(2×2-3)2=1.0m v=4(2×2-3)=4m/s and a=8m/s2

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A particle starts moving along a straight line path with a velocity 10 m s-1. After 5 s, the distance of the particle from the starting point is 50 m. Which of the following statement about the nature of motion of the particle are correct? 


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