First slide

Ray optics

Question

A motor car is fitted with a convex driving mirror of focal length 20 cm. A second motor car 2.01 m broad and 1.005m high is 40 m behind the first car. The size of the image of the second car seen in the mirror of the first, is.

Easy

A

Breadth = 8cm, height = 4 cm
B

Breadth = 1cm, height = 0.5 cm
C

Breadth = 12cm, height = 6 cm
D

Breadth = 14cm, height = 7 cm

Solution

f = 20cm, u = -4000cm. Using , $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$ we get .v= $\frac{4000}{201} c m$
Also m= $\frac{I}{O} = \frac{v}{u} =$ $\frac{4000}{201} \times \frac{1}{4000} = \frac{1}{201}$
Size of the image = $\frac{1}{201}$ (size of object)

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