A motor car is moving with speed 30 ms-1 on a circular path of radius 500 m. Its speed is increasing at the rate of 2 ms-2, what will be its resultant acceleration?

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2.5 ms-2

2.7 ms-2

2 ms-2

4.5 ms-2

answer is B.

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Detailed Solution

Resultant acceleration,a = [(v2r)2+(2)2]12 = [(30×30500)2+4]12= [8125+4]12 = 2.7 ms-2

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