First slide

Work done by Diff type of forces

Question

The motor connected to A (not shown) is pulling up the 200 kg block along the rough incline with constant speed of 5 m/s when power output of motor is 10 kW. If the power out put of motor is suddenly increased to 15 kW then the acceleration of block just after increasing the power is.

Easy

A

$5 m / s^{2}$
B

$1 m / s^{2}$
C

Zero
D

can’t be computed from the given information.

Solution

When the block is moving with constant velocity v then
$T = μN + 200 g \sin 37^{0}$
$TV = 10 \ times {10^3} & & \ mu N = 800 N$
$When P^{1} = 15 kW, then T^{1} = \frac{15 \times 10^{3}}{5} = 3000 N$
$T^{1} - μN - 200 gsin 37^{0} = 200 a \Rightarrow a = 5 m / s^{2}$

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