A motor cyclist is trying to jump across a path as shown by driving horizontally off a cliff A at a speed of 5 ${ms}^{- l}$ . Ignore air resistance and take g = l0 ${ms}^{- 2}$ . Th" speed with which he rouches the peak -B is:

Question

Infinity Learn · Accepted Answer

Speed in horizontal direction remains constant during whole journey because there is no acceleration in this direction.So, vh $$=$$ $$6$$ $$ms-1In$$ vertical direction:Loss of gravitation potential energy $$=$$ gain in KEi.e., $$mgh$$ $$=$$ $$12mvV2$$        $$vV2$$ $$=$$ $$2gh$$ $$=$$ $$2$$×$$10$$×(70-60) $$=$$ $$200Hence$$, the speed with which he touches the cliff B isv $$=$$ $$vB2+vV2$$ $$=$$ $$25+200$$ $$=$$ $$225$$ $$=$$ $$15$$ $$ms-1$$

A motor cyclist is trying to jump across a path as shown by driving horizontally off a cliff A at a speed of 5 ${ms}^{- l}$ . Ignore air resistance and take g = l0 ${ms}^{- 2}$ . Th" speed with which he rouches the peak -B is:

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A motor cyclist is trying to jump across a path as shown by driving horizontally off a cliff A at a speed of 5 ms-l. Ignore air resistance and take g = l0 ms-2. Th" speed with which he rouches the peak -B is:

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A motor cyclist is trying to jump across a path as shown by driving horizontally off a cliff A at a speed of 5 ${ms}^{- l}$ . Ignore air resistance and take g = l0 ${ms}^{- 2}$ . Th" speed with which he rouches the peak -B is: