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Q.

The motor of an engine is rotating about its axis with an angular velocity of 100 rev min-1. It come to rest in 15s, after being switched off. Assuming constant angular deceleration. What are the number of revolutions made by it before coming to rest?

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a

15.6

b

32.6

c

12.5

d

40

answer is C.

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Detailed Solution

As ωf=ωi+αtHere, 0=ω0−αt∴ α=ω0t=(100×2π)/6015=0.7rads−2Angle rotated before coming to rest,θ=ω022αθ=100×2π6022×0.7=78.33radHence, number of rotations, n=θ2π=78.332π=12.5
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