Q.

A motor of power P0 is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe n times, the power of the motor is increased to P1. The ratio of P1 to P0 is :

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a

n : 1

b

n2 : 1

c

n3 : 1

d

n4 : 1

answer is C.

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Detailed Solution

If Q be the discharge , V be the velocity of water and A be the cross-sectional area , then Q = AV..:m = Rate of mass flow = PQ.: power , P = 1/2 m V2 = 1/2 (PQ) (Q/A)2.: P α Q3.: P1 / P0 = (nQ)3/(Q)3 = n3
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