A motor of power $$P0$$ is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe n times, the power of the motor is increased to $$P1$$. The ratio of $$P1$$ to $$P0$$ is :

Question

Infinity Learn · Accepted Answer

If Q be the discharge , V be the velocity of water and A be the $$cross-sectional$$ area , then Q $$=$$ AV..:m $$=$$ Rate of mass flow $$=$$ PQ.: power , P $$=$$ $$1/2$$ m $$V2$$ $$=$$ $$1/2$$ (PQ) $$(Q/A)2$$.: P α $$Q3$$.: $$P1$$ $$/$$ $$P0$$ $$=$$ $$(nQ)3/(Q)3$$ $$=$$ $$n3$$

A motor of power P₀ is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe n times, the power of the motor is increased to P₁. The ratio of P₁ to P₀ is :

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A motor of power P0 is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe n times, the power of the motor is increased to P1. The ratio of P1 to P0 is :

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A motor of power P₀ is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe n times, the power of the motor is increased to P₁. The ratio of P₁ to P₀ is :