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Questions  

A motor pump of power 4 H.P is discharging water with a velocity of 5ms1 .  In order to discharge water with a velocity of 15ms1 , the power of the motor should be

a
2 H.P
b
108 H.P
c
72 H.P
d
36 H.P

detailed solution

Correct option is B

P∝V3 P1P2=V13V23⇒4P2=(515)3=127 P2=27×4=108  H.P.

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