A motor pump of power 4 H.P is discharging water with a velocity of 5 ms−1 . In order to discharge water with a velocity of 15 ms−1 , the power of the motor should be

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2 H.P

108 H.P

72 H.P

36 H.P

answer is B.

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Detailed Solution

P∝V3 P1P2=V13V23⇒4P2=(515)3=127 P2=27×4=108 H.P.

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