Download the app

Questions  

A motorcyclist moving with a velocity of 144 kmh-1 on a flat road takes a turn on the road at a point,
where the radius of curvature of the road is 40 m. The acceleration due to gravity is 10 ms-2. In order
to avoid sliding, he must bend with respect to the vertical plane by an angle

a
θ=tan-1(4)
b
θ  =  450
c
θ=tan-1(2)
d
θ=tan-1(6)

detailed solution

Correct option is A

Given,  v=144kmh-1=144×518 ms-1=40 ms-1∴  tanθ=v2Rg=(40)240×10=1600400=4⇒  θ=tan-1(4)

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

For traffic moving at 60 km/ hour along a circular track of radius 0⋅1 km, the correct angle of banking is


phone icon
whats app icon