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Q.

A moving car possesses average velocities of 5 ms-1, 10 ms-1 and 15 ms-1 in the first, second, and third seconds respectively. What is the total distance covered by the car in these 3 s?

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a

15 m

b

30 m

c

55 m

d

None of these

answer is B.

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Detailed Solution

Distance covered : =S=vav× time =V+u2tFor first second: S1=5×1=5mFor second second: S2=10×1=10mFor third second: S3=15×1=15mTotal distance travelledS=S1+S2+S3=5+10+15=30m
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