Questions
A moving car possesses average velocities of 5 ms-1, 10 ms-1 and 15 ms-1 in the first, second, and third seconds respectively. What is the total distance covered by the car in these 3 s?
detailed solution
Correct option is B
Distance covered : =S=vav× time =V+u2tFor first second: S1=5×1=5mFor second second: S2=10×1=10mFor third second: S3=15×1=15mTotal distance travelledS=S1+S2+S3=5+10+15=30mSimilar Questions
A runner travels around a rectangular track of length 70m and width 30m. After travels around the rectangular track two times, runner back to starting point. Determine distance travelled by the runner.
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