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Q.

A moving car possesses average velocities of 5 ms-1, 10 m/s and 15 m/s in the first, second and third seconds respectively. What is the total distance covered by the car in these three seconds?

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a

15 m

b

30 m

c

55 m

d

None of these

answer is B.

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Detailed Solution

distance covered = s = vav×timeFor 1st second: S1 = 5×1 = 5 mFor 2nd second : S2 = 10×1 = 10 mFor 3rd second : S3 = 15 ×1 = 15 mTotal distance traveledS = S1+S2+S3 = 5 +10+15 = 30 m
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