Questions
A moving car possesses average velocities of 5 , 10 m/s and 15 m/s in the first, second and third seconds respectively. What is the total distance covered by the car in these three seconds?
detailed solution
Correct option is B
distance covered = s = vav×timeFor 1st second: S1 = 5×1 = 5 mFor 2nd second : S2 = 10×1 = 10 mFor 3rd second : S3 = 15 ×1 = 15 mTotal distance traveledS = S1+S2+S3 = 5 +10+15 = 30 mTalk to our academic expert!
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A man moves from home to market which is at a distance of 2 km with a speed of 3 kmph. Finding the market closed he instantly returns home with a speed 6 kmph. The average velocity of the man in the total journey is
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