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Moving coil Galvanometer

Question

A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be

Moderate
Solution

Voltage{\text{ }}sensitivity = \frac{{{\text{Current sensitivity}}}}{{{\text{Resistance of galvanometer}}\,{\text{G}}}}

\Rightarrow G = \frac{{10}}{2} = 5\,\Omega

Here\;{i_g} = Full{\text{ }}scale{\text{ }}deflection{\text{ }}current = \frac{{150}}{{10}} = 15\,mA

V = Voltage to be measured = 150 x 1 = 150 V.

Hence\,\,R = \frac{V}{{{i_g}}} - G = \frac{{150}}{{15 \times {{10}^{ - 3}}}} - 5 = 9995\,\Omega



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Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is


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