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Q.

A moving coil galvanometer has 50 turns and each turn has an area 2×10−4m2. The magnetic field produced by the magnet inside the galvanometer is  0.02T. The torsional constant  of the suspension wire is  10−4Nm rad−1. When a current flows through the galvanometer, a full scale deflection occurs if the coil rotates by  0.2rad. The resistance of the coil of the galvanometer is  50Ω. This galvanometer is to be converted into an ammeter capable of measuring current in the range  0−1.0A. For this purpose, a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance, in ohms,is…..

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answer is 5.56.

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Detailed Solution

N = 50 turns                        A=2×10−4 m2                    B=0.02 T                    K=10−4 Qm=0.2 rad                        Rg=50Ω                         IA=0-1.0A               τ=MB=Cθ      here M=NIASo , BINA=Cθ                         ⇒0.02×ig×50×2×10−4=10−4×0.2                 ⇒Ig=0.1AFor galvanometer, resistance is to be connected to ammeter in shunt.The resistance to be connected in parallel to ammeter.Ig×Rg=I−IgS      ⇒0.1×50=1−0.1S     ⇒S=509=5.555Ω=5.56 ohm
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